If It Touches The Vertical Axis It Is Called An Equation Of Circle Touching.
Then the locus of the centre of this circle, is : Also , given that the circle touches the x axis. Equation of a circle with centre (4, 3) touching the circle x^2 + y^2 = 1 is;
Let C ( X 1, Y 1) Be.
The centre of a circle passing through the points (0, 0) , (1, 0) and touching the circle x^2 + y^2… The point of tangency will be the closest point to the circle on the x axis. Solution to this particular problem become easier if one try a rough sketch to the circle under the given condition & utilizing its geometry.
As A Rule Of Thumb, The Shortest Distance Between A Point (3,4) And A Line (X=0) Will Be Perpendicular To The.
We know that the center of the circle is at negative 54 in its tangent to the x axis that center at negative 54 let's just say this is negative five for at the center of the circle that it's. The equation of circle is x 2+y 2+2gx+2fy+c=0the center of circle is (−g,−f) comparing it with (−2,3) g=2,f=−3the equation with center (−2,3) is x 2+y 2+4x−6y+c=0the equation touches x.